Where Does The Hiv Rash Occur

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For example we know that in reality in the city many people live in buildings and few in the streets, if it is represented on a graph would be that strong discontinuities. Instead if you represent in each point the average number of inhabitants per square meter in a radius of 20 meters could have a function "almost" continuous "roll. Although the population density does not respond point by point with reality not appear to be a bad idea to use as a guide for building in the city depending on which areas etc equipment.

The volume of a city can be used for certain uses, which may be listed:

Housing: citizens staying Transportation: roads and other

offers several: shops, workplaces etc.

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T is the density of transport networks S S = p * P + T + t * o * O

where letters are constants and S

is the value that is saturated.

MAXIMUM RIDE AND ACCESS AREA

To calculate the maximum possible in this city tour you must first determine what percentage of the population that is trying to go somewhere, this percentage will be called k . This population will be on the roads so that the population density on the road is
. If T (input flow) you divide this amount
k * P (the tube section ) would get the speed at which this population is displaced by highways. So you have to V = T / (k * P) .

Assuming constant k to save the integration, and I feel

t
the time available has to be the most feasible route by a citizen in this city is X = (T * t) / (2k * P) , who is also the radius of the circle or sphere to which you can access the city, or seen another way is the radius from which citizens can get a certain point. The 2 includes the need to contemplate the return journey.

As is reasonable, the access area decreases with density and increases the capacity of transport.

UNITS Units must be consistent between them, this is sufficient, but to establish a system: k = dimensionless P = hab/m2 T = (m * rm) / (s * m2) T = seconds

X = meters

V = m / s

O = ud / (s * m2) PRACTICAL EXAMPLE OF TOWN I; HEIGHT OF BUILDINGS AND LAND USE

Despite

the simplistic model, we see that yields results. There is a city where land can be used to make roads or buildings. T

is proportional to the area devoted to roads and

P is proportional to the area occupied by buildings and the number of floors H of these. Also the higher the building the greater the time spent down the elevator, the time lost responding to
H / v
where
H

speed v
is defined as the proportion of buildings, then the proportion of roads is
. Therefore
c
is a constant, on the other hand

. The time available
t is obtained by subtracting the total time tt
time spent in the elevator, thus remaining
t = tt-2 * H / v

by up and down. It is seen that there are many parameter, eye can try to give some values \u200b\u200bfor a typical city such as Bilbao. Data: k = 0.3, it is expected that this percentage at certain times of day the inhabitants are all trying to go somewhere. Tt

= 7200 seconds, ie people willing to spend 2 hours on their travels round-trip.

hab/m2 d = 0.04, ie every 25 m2 of floor of city home to a resident if roads are built. v = 0.125 plants / s, ie one plant every 8 seconds, taking into account the need to call the lift .. c = 1.2 (m * rm) / (s * m2), with note that at an average speed of 10m / s in the city there 0.12hab/m2 on the road (if moving more slowly would have more inhabitants) X = 50,000 feet, assume that interest is reached that distance as in this area are the factories and so on. Substituting

all in the formula of distance, it was time the MathType: